document.write( "Question 331890: A rectangular picture is 3 inches longer than it is wide. It has a frame 2 inches wide whose area is 92 square inches. Find the dimensions of the picture. \n" ); document.write( "
Algebra.Com's Answer #237905 by mananth(16946)\"\" \"About 
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let width of picture be x
\n" ); document.write( "length = x+3
\n" ); document.write( "..
\n" ); document.write( "width =2 inches\r
\n" ); document.write( "\n" ); document.write( "width including frame = x+2
\n" ); document.write( "length including frame = x+3+2
\n" ); document.write( "..
\n" ); document.write( "Total area = (x+2)(x+5)
\n" ); document.write( "=x^2+7x+10
\n" ); document.write( "..
\n" ); document.write( "area of picture alone = x(x+3)
\n" ); document.write( "=x^2+3x
\n" ); document.write( "..
\n" ); document.write( "x^2+7x+10-x^2-3x = area of frame
\n" ); document.write( "4x+10= 92
\n" ); document.write( "4x=92-10
\n" ); document.write( "4x=82
\n" ); document.write( "x=20.5 cm the width
\n" ); document.write( "length = 20.5+2= 22.5 cm\r
\n" ); document.write( "\n" ); document.write( "CHECK
\n" ); document.write( "((22.5)*(25.5))-(20.5*(20.5+3))=92
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