document.write( "Question 331904: Solve using the five-step problem-solving process. Show all steps necessary to arrive at your solution.\r
\n" ); document.write( "\n" ); document.write( "The second angle of a triangle is 3 times as large as the first. The third angle is 55° more than the first. Find the measure of the smallest angle.
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Algebra.Com's Answer #237900 by mananth(16946)\"\" \"About 
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let first angle = x
\n" ); document.write( "second angle = 3x
\n" ); document.write( "third angle = x+55
\n" ); document.write( "..
\n" ); document.write( "The sum of angles of triangle = 180(deg)
\n" ); document.write( "x+3x+x+55=180
\n" ); document.write( "5x+55=180
\n" ); document.write( "add -55
\n" ); document.write( "5x+55-55=180-55
\n" ); document.write( "5x=125
\n" ); document.write( "divide by 5
\n" ); document.write( "5x/5=125/5
\n" ); document.write( "x=25
\n" ); document.write( "first angle 25 deg
\n" ); document.write( "second angle = 3x= 75 deg
\n" ); document.write( "third angle = x+55 = 25+55=80 deg.
\n" ); document.write( "CHECK
\n" ); document.write( "80+75+25=180
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