document.write( "Question 331844: A cyclist who walks up the hills, rides 5 times as fast as he walks. If he cycles at 16 k.m/h and walks at 4 k.m/h then find his average speed over journey. \n" ); document.write( "
Algebra.Com's Answer #237886 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! In order for this problem to make sense, I changed the word \"fast\" to \"far\" \n" ); document.write( ": \n" ); document.write( "A cyclist who walks up the hills, rides 5 times as far as he walks. \n" ); document.write( " If he cycles at 16 k.m/h and walks at 4 k.m/h then find his average speed over journey. \n" ); document.write( ": \n" ); document.write( "Let a = his average speed \n" ); document.write( ": \n" ); document.write( "let d = distance he walked \n" ); document.write( "and \n" ); document.write( "5d = distance he rode \n" ); document.write( "then \n" ); document.write( "6d = total distance \n" ); document.write( ": \n" ); document.write( "Write a time equation; Time = dist/speed \n" ); document.write( ": \n" ); document.write( "walk time + cycle time = total time \n" ); document.write( " \n" ); document.write( "multiply equation by 16a, to eliminate the denominators, results \n" ); document.write( ": \n" ); document.write( "4ad + 5ad = 16(6d) \n" ); document.write( "9ad = 96d \n" ); document.write( "divide both sides by d \n" ); document.write( "9a = 96 \n" ); document.write( "a = \n" ); document.write( "a = 10 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "check solution by finding a value for d, assume d=5 km \n" ); document.write( "he rode 25 km, walked 5 km, total 30 km \n" ); document.write( " \n" ); document.write( "1.25 + 1.5625 = 2.8125; confirms our solution \n" ); document.write( " |