document.write( "Question 331844: A cyclist who walks up the hills, rides 5 times as fast as he walks. If he cycles at 16 k.m/h and walks at 4 k.m/h then find his average speed over journey. \n" ); document.write( "
Algebra.Com's Answer #237886 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
In order for this problem to make sense, I changed the word \"fast\" to \"far\"
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\n" ); document.write( "A cyclist who walks up the hills, rides 5 times as far as he walks.
\n" ); document.write( " If he cycles at 16 k.m/h and walks at 4 k.m/h then find his average speed over journey.
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\n" ); document.write( "Let a = his average speed
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\n" ); document.write( "let d = distance he walked
\n" ); document.write( "and
\n" ); document.write( "5d = distance he rode
\n" ); document.write( "then
\n" ); document.write( "6d = total distance
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\n" ); document.write( "Write a time equation; Time = dist/speed
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\n" ); document.write( "walk time + cycle time = total time
\n" ); document.write( "\"d%2F4\" + \"%285d%29%2F16\" = \"%286d%29%2Fa\"
\n" ); document.write( "multiply equation by 16a, to eliminate the denominators, results
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\n" ); document.write( "4ad + 5ad = 16(6d)
\n" ); document.write( "9ad = 96d
\n" ); document.write( "divide both sides by d
\n" ); document.write( "9a = 96
\n" ); document.write( "a = \"96%2F9\"
\n" ); document.write( "a = 10\"2%2F3\" km/hr is his average speed
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\n" ); document.write( "check solution by finding a value for d, assume d=5 km
\n" ); document.write( "he rode 25 km, walked 5 km, total 30 km
\n" ); document.write( "\"5%2F4\" + \"25%2F16\" = \"30%2F10.67\"
\n" ); document.write( "1.25 + 1.5625 = 2.8125; confirms our solution
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