document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331852>Question 331852</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sail boat travels 20 miles downstream in 3 hours. I returns in 4 hours. Find the speed of the sailboat in still water and the rate of the current.<BR>\n" );
document.write( "I know its 35/6 for speed and 5/6 but how can I check this out? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237849 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> downstream:  Boat speed + current speed = total speed downstream =20/3 (distance/time)<BR>\n" );
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document.write( "so B+C=20/3<BR>\n" );
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document.write( "upstream:  Boat speed - current speed = total speed upstream =20/4 (distance/time)<BR>\n" );
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document.write( "so B-C=20/4=5\r<BR>\n" );
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document.write( "==<BR>\n" );
document.write( "you have the solutions B=35/6, C=5/6<BR>\n" );
document.write( "to check that these are in fact the solutions\r<BR>\n" );
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document.write( "just substitute these values into either B+C=20/3 or B-C=5 and see if left side of the equation equals the right side </SPAN>\n" );
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