document.write( "Question 331839: The equation h=-16^2 +112t gives the height (h) of an arrow shot upward from the ground with an initial velocity of 112ft/s, where t represents the time after the arrow leaves the ground. Using that equation, find the height of the arrow after (a)2seconds (b)5 seconds \n" ); document.write( "
Algebra.Com's Answer #237847 by Alan3354(69443)\"\" \"About 
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It's h(t) = -16t^2 +112t
\n" ); document.write( "Sub 2 for t
\n" ); document.write( "h(2) = -16*4 + 112*2 = 224-64
\n" ); document.write( "h(2) = 160 feet
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\n" ); document.write( "Do the same with 5
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