document.write( "Question 331795: If a boater can travel 22 miles downstream in the same time it takes to travel 16 miles upstream, with a current of 4 mi/h, what is the rate of the boat instill water? I know the formula for distance, but I can't seem to set up the equation correctly. Please help me! \n" ); document.write( "

Algebra.Com's Answer #237835 by jrfrunner(365) $\"\"$ $\"About$

You can put this solution on YOUR website!
distance = rate*time or speed *time\r
\n" ); document.write( "\n" ); document.write( "downstream the speed is Boat + current speed : B+C
\n" ); document.write( "upstream the speed is Boat -current speed: B-C
\n" ); document.write( "--
\n" ); document.write( "22miles = (B+C)*t=Bt+Ct
\n" ); document.write( "16miles = (B-C)*t=Bt-Ct
\n" ); document.write( "--
\n" ); document.write( "since C (current speed)=4
\n" ); document.write( "22miles =(B+4)*t=B*t+4t
\n" ); document.write( "16 miles =(B-4)*t=B*t-4*t
\n" ); document.write( "--
\n" ); document.write( "add these two equations
\n" ); document.write( "--
\n" ); document.write( "38 = 2Bt
\n" ); document.write( "solve for t: t=38/(2B)=19/B
\n" ); document.write( "subsitute t into one of the orginal equations
\n" ); document.write( "---
\n" ); document.write( "22 = B(19/B) + 4(19B)
\n" ); document.write( "22=19+76/B\r
\n" ); document.write( "\n" ); document.write( "can you handled it from here, by solving for B (the boat speed in still water)? \n" ); document.write( "

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