document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331705>Question 331705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please answer this: the width of a rectangular window frame is 12 inches less than its length. if you add 30 inches to both the length and the width, you double the perimeter. find the length and the width of the original rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237828 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237828\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the width of a rectangular window frame is 12 inches less than its length.<BR>\n" );
document.write( " if you add 30 inches to both the length and the width, you double the perimeter.<BR>\n" );
document.write( " find the length and the width of the original rectangle?<BR>\n" );
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document.write( "Find the original perimeter (P1)<BR>\n" );
document.write( "P1 = 2L + 2W<BR>\n" );
document.write( "\"the width of a rectangular window frame is 12 inches less than its length.\"<BR>\n" );
document.write( "P1 = 2L + 2(L-12)<BR>\n" );
document.write( "P1 = 2L + 2L - 24<BR>\n" );
document.write( "p1 = 4L - 24, the original perimeter<BR>\n" );
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document.write( "Find the doubled perimeter<BR>\n" );
document.write( "\"if you add 30 inches to both the length and the width,\"<BR>\n" );
document.write( "P2 = 2(L+30) + 2(W+30)<BR>\n" );
document.write( "P2 = 2L + 60 + 2W + 60<BR>\n" );
document.write( "P2 = 2L + 2W + 120<BR>\n" );
document.write( "Replace W with (L-12)<BR>\n" );
document.write( "P2 = 2L + 2(L-12) + 120<BR>\n" );
document.write( "P2 = 2L + 2L - 24 + 120<BR>\n" );
document.write( "P2 = 4L + 96,<BR>\n" );
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document.write( "It says the new perimeter = twice the old perimeter; P2 = 2(P1)<BR>\n" );
document.write( "4L + 96 = 2(4L - 24)<BR>\n" );
document.write( "4L + 96 = 8L - 48<BR>\n" );
document.write( "96 + 48 = 8L - 4L<BR>\n" );
document.write( "144 = 4L<BR>\n" );
document.write( "L = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=144%2F4 ALIGN=MIDDLE  ALT=\"144%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "L = 36 in is the original length<BR>\n" );
document.write( "then<BR>\n" );
document.write( "36 - 12 = 24 in is the original width<BR>\n" );
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document.write( ":<BR>\n" );
document.write( "You can check the solution by finding the old and the new perimeters\r<BR>\n" );
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document.write( " </SPAN>\n" );
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