document.write( "Question 331802: What is the equation of a circle touching the lines x-3y-11=0 and 3x-y-9=0 and having its center on the line x+2y+19=0. \n" ); document.write( "
Algebra.Com's Answer #237827 by Alan3354(69443)\"\" \"About 
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What is the equation of a circle touching the lines x-3y-11=0 and 3x-y-9=0 and having its center on the line x+2y+19=0.
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\n" ); document.write( "Find the bisector of the two tangent lines, x-3y-11=0 and 3x-y-9=0.
\n" ); document.write( "To do that, find the intersection of the 2 lines.
\n" ); document.write( "The slope of the bisector is tan(arctan(1 line) + arctan(other line))
\n" ); document.write( "The slope = 1
\n" ); document.write( "With the slope and the point of intersection, find the equation of the bisector.
\n" ); document.write( "Then find the intersection of the bisector and the line x+2y+19 = 0. That's the center of the circle.
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\n" ); document.write( "Find the distance from the center to either x-3y-11=0 or 3x-y-9=0, that's the radius.
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\n" ); document.write( "email for any assistance needed at moralloophole@aol.com
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