document.write( "Question 331710: a car travels from one town to another at a speed of 42mph. if it had gone 6mph faster, it could have made the trip in a half hour less time. how far apart are the towns? \n" ); document.write( "
Algebra.Com's Answer #237826 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a car travels from one town to another at a speed of 42mph. \n" ); document.write( " if it had gone 6mph faster, it could have made the trip in a half hour less time. \n" ); document.write( "how far apart are the towns? \n" ); document.write( ": \n" ); document.write( "Let d = dist between the towns \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "actual time - faster time = half-hour \n" ); document.write( " \n" ); document.write( "Mult by 2016 (that's 42*48); results \n" ); document.write( "48d - 42d = 1008 \n" ); document.write( ": \n" ); document.write( "6d = 1008 \n" ); document.write( "d = \n" ); document.write( "d = 168 mi between towns \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the times \n" ); document.write( "168/42 = 4 hrs \n" ); document.write( "168/48 = 3.5 \n" ); document.write( "-------------- \n" ); document.write( "differ = .5 hr confirms our solution of 168 mi \n" ); document.write( " |