document.write( "Question 331710: a car travels from one town to another at a speed of 42mph. if it had gone 6mph faster, it could have made the trip in a half hour less time. how far apart are the towns? \n" ); document.write( "
Algebra.Com's Answer #237826 by ankor@dixie-net.com(22740)\"\" \"About 
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a car travels from one town to another at a speed of 42mph.
\n" ); document.write( " if it had gone 6mph faster, it could have made the trip in a half hour less time.
\n" ); document.write( "how far apart are the towns?
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\n" ); document.write( "Let d = dist between the towns
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\n" ); document.write( "Write a time equation; time = dist/speed
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\n" ); document.write( "actual time - faster time = half-hour
\n" ); document.write( "\"d%2F42\" - \"d%2F48\" = \"1%2F2\"
\n" ); document.write( "Mult by 2016 (that's 42*48); results
\n" ); document.write( "48d - 42d = 1008
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\n" ); document.write( "6d = 1008
\n" ); document.write( "d = \"1008%2F6\"
\n" ); document.write( "d = 168 mi between towns
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\n" ); document.write( "Check solution by finding the times
\n" ); document.write( "168/42 = 4 hrs
\n" ); document.write( "168/48 = 3.5
\n" ); document.write( "--------------
\n" ); document.write( "differ = .5 hr confirms our solution of 168 mi
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