document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331766>Question 331766</A>: <I><SPAN STYLE=\"word-break: break-all;\"> we have a pile of dirt with the measurements of 26 ft wide base, 100 ft long, and 8 ft high, how do we measure this and turn it into cubic yards, this is more of a right triangle than triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237821 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we have a pile of dirt with the measurements of 26 ft wide base, 100 ft long, and 8 ft high, how do we measure this and turn it into cubic yards, this is more of a right triangle than triangle\r<BR>\n" );
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document.write( "3 feett = 1yard<BR>\n" );
document.write( "26 feet = 26/3 = 8.66 yards<BR>\n" );
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document.write( "100 feet = 100/3= 33.33 yards<BR>\n" );
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document.write( "8 feet = 8 / 3 = 2.66 yards\r<BR>\n" );
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document.write( "Volume = 8.66*33.33*2.66 <BR>\n" );
document.write( "= 767.77 cu. yards\r<BR>\n" );
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document.write( "This cannot be a triangle . triangle is two dimensional.<BR>\n" );
document.write( "this can be represented as a cuboid<BR>\n" );
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