document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331756>Question 331756</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please show me how to use substitution to solve the system of equations;<BR>\n" );
document.write( "5x+5y=-30 and 2x-y=15. Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237817 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237817\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please show me how to use substitution to solve the system of equations;<BR>\n" );
document.write( "5x+5y=-30 and 2x-y=15<BR>\n" );
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document.write( "5x+5y=-30 --> x+y = -6  reduce whenever possible<BR>\n" );
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document.write( "2x-y=15<BR>\n" );
document.write( "Solve for y<BR>\n" );
document.write( "y = 2x - 15<BR>\n" );
document.write( "Sub for y into the 1st eqn<BR>\n" );
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document.write( "x+y = -6<BR>\n" );
document.write( "x + (2x-15) = -6<BR>\n" );
document.write( "Solve for x.<BR>\n" );
document.write( "Then sub the number for x and solve for y\r<BR>\n" );
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document.write( " </SPAN>\n" );
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