document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331763>Question 331763</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling 80 mph and train b is traveling 100 mph. Train A passes a station at 6:15 am. If train B passes the same station at 6:27 am, at what time will train B catch up to train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237813 by </B><A HREF=/tutors/aboutme.mpl?userid=mathmandotcom><B>mathmandotcom(31)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathmandotcom><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237813\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The solution to this problem lies in the equation d=rt<BR>\n" );
document.write( "d=distance; da=distance train a travels, db=distance train b travels<BR>\n" );
document.write( "r=rate;     ra=80, rb=100<BR>\n" );
document.write( "t=time;      ta= time for train a, tb=time for train b<BR>\n" );
document.write( "---------------------------------------------------------------------<BR>\n" );
document.write( "da=db so ta*ra=tb*rb   train A has a head start by 12 minutes or 80*12/60=16m<BR>\n" );
document.write( "da=16+80t=100t=db<BR>\n" );
document.write( "16+80t=100t  subtract 80t<BR>\n" );
document.write( "16=20t       divide by 20<BR>\n" );
document.write( "4/5=t in hours in minutes 4/5*60=48minutes; answer </SPAN>\n" );
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