document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331753>Question 331753</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much pure alcohol should be added to 400 ml. of 15% strength to make its strength 32%?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237804 by </B><A HREF=/tutors/aboutme.mpl?userid=mathmandotcom><B>mathmandotcom(31)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathmandotcom><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237804\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .15(400) +1x=.32(400+x):   1=100% x=amount of prue alcohol needed<BR>\n" );
document.write( "60+x=120+.32x: subtract 60 from both sides<BR>\n" );
document.write( "x=60+.32x:    subtract .32x from both sides<BR>\n" );
document.write( ".68x=60;       divide by .68<BR>\n" );
document.write( "x=60/.68;   simplify<BR>\n" );
document.write( "x=88.235ml at least  </SPAN>\n" );
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