document.write( "Question 331707: Two students are 350 m apart and begin walking toward one another at constant rates. One travels at 1.6 m/s and other at 1.9 m/s. how long will they walk until they meet? how far has each of them gone? \n" ); document.write( "
Algebra.Com's Answer #237796 by mananth(16949) You can put this solution on YOUR website! let one travel x meters before they meet. \n" ); document.write( "the other will walk 350-x meters\r \n" ); document.write( "\n" ); document.write( "speed of one is 1.6 m / s \n" ); document.write( "other is 1.9 m/s \n" ); document.write( ".. \n" ); document.write( "the time they walk before they meet is the same. \n" ); document.write( "x/1.6 = 350-x/1.9 \n" ); document.write( "1.9x=1.6(350-x) \n" ); document.write( "1.9x=560-1.6x \n" ); document.write( "2.5x=560 \n" ); document.write( "x=560/2.5 \n" ); document.write( "x= 224 m \n" ); document.write( "the other travels 350-244=106 m \n" ); document.write( ".. \n" ); document.write( "the time they meet will be \n" ); document.write( "224/1.6 =140 seconds after they start \n" ); document.write( " |