document.write( "Question 331707: Two students are 350 m apart and begin walking toward one another at constant rates. One travels at 1.6 m/s and other at 1.9 m/s. how long will they walk until they meet? how far has each of them gone? \n" ); document.write( "
Algebra.Com's Answer #237796 by mananth(16949)\"\" \"About 
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let one travel x meters before they meet.
\n" ); document.write( "the other will walk 350-x meters\r
\n" ); document.write( "\n" ); document.write( "speed of one is 1.6 m / s
\n" ); document.write( "other is 1.9 m/s
\n" ); document.write( "..
\n" ); document.write( "the time they walk before they meet is the same.
\n" ); document.write( "x/1.6 = 350-x/1.9
\n" ); document.write( "1.9x=1.6(350-x)
\n" ); document.write( "1.9x=560-1.6x
\n" ); document.write( "2.5x=560
\n" ); document.write( "x=560/2.5
\n" ); document.write( "x= 224 m
\n" ); document.write( "the other travels 350-244=106 m
\n" ); document.write( "..
\n" ); document.write( "the time they meet will be
\n" ); document.write( "224/1.6 =140 seconds after they start
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