document.write( "Question 331728: Solve the system: y^2=1-x^2
\n" ); document.write( " y^2=x^2-3x+2
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Algebra.Com's Answer #237791 by mananth(16946)\"\" \"About 
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y^2=1-x^2
\n" ); document.write( "y^2=x^2-3x+2
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\n" ); document.write( "x^2-3x+2=1-x^2
\n" ); document.write( "2x^2-3x+1=0
\n" ); document.write( "2x^2-2x-x+1=0
\n" ); document.write( "2x(x-1)-1(x-1)=0
\n" ); document.write( "(x-1)(2x-1)=0
\n" ); document.write( "x=1 OR 1/2
\n" ); document.write( "plug the value of x to get value of y
\n" ); document.write( "y=0 OR sqrt 3/4
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