document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331693>Question 331693</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dear Sir/Madam; Pls. kindly see the problem below:\r<BR>\n" );
document.write( "\n" );
document.write( "Question: In three years, Janice will be three times as old as her daughter. Six years ago, her age was her daughter's age squared. How old is Janice? \r<BR>\n" );
document.write( "\n" );
document.write( "I wrote out an Algebraic expression for this problem as follows: denoting the daughter's age by x to be able to solve for her daughter's age first, so Janice's age in three years would be: 3x+3, and her age six years ago would have been x2-6; x2-6+3x+3=0, which when simplified will look like this; x2+3x-3=0. But I do not think I am right. Could you please help. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237783 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237783\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let daughter's age be x now.<BR>\n" );
document.write( "after 3 years daughter will be x+3<BR>\n" );
document.write( "..<BR>\n" );
document.write( "after 3 years Janice will be 3*(x+3) years<BR>\n" );
document.write( "..<BR>\n" );
document.write( "6 years ago daughter's age = x-6.<BR>\n" );
document.write( "janice ' age was  (x-6)^2<BR>\n" );
document.write( "..<BR>\n" );
document.write( "3x+9-9 =3x<BR>\n" );
document.write( "3x= (x-6)^2<BR>\n" );
document.write( "3x=x^2-12x+36<BR>\n" );
document.write( "x^2-15x+36=0<BR>\n" );
document.write( "x^2-12x-3x+36=0<BR>\n" );
document.write( "x(x-12)-3(x-12)=0<BR>\n" );
document.write( "(x-12)(x-3)=0<BR>\n" );
document.write( "x=12 OR 3\r<BR>\n" );
document.write( "\n" );
document.write( "After 3 years Janice will be x(x+3) <BR>\n" );
document.write( "plug value of x <BR>\n" );
document.write( "3(12+3)=45<BR>\n" );
document.write( "So now Janice  will be 45-3 = 42 years ( this makes sense)\r<BR>\n" );
document.write( "\n" );
document.write( "..<BR>\n" );
document.write( "For value x=3<BR>\n" );
document.write( "3(x+3)<BR>\n" );
document.write( "plug value of 3<BR>\n" );
document.write( "3(3+3)= 18 This was 3 years later<BR>\n" );
document.write( "now she will be 15 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );