document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331693>Question 331693</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dear Sir/Madam; Pls. kindly see the problem below:\r<BR>\n" );
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document.write( "Question: In three years, Janice will be three times as old as her daughter. Six years ago, her age was her daughter's age squared. How old is Janice? \r<BR>\n" );
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document.write( "I wrote out an Algebraic expression for this problem as follows: denoting the daughter's age by x to be able to solve for her daughter's age first, so Janice's age in three years would be: 3x+3, and her age six years ago would have been x2-6; x2-6+3x+3=0, which when simplified will look like this; x2+3x-3=0. But I do not think I am right. Could you please help. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237771 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237771\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In three years, Janice will be three times as old as her daughter.<BR>\n" );
document.write( "j + 3 = 3(d+3)<BR>\n" );
document.write( "j + 3 = 3d + 9<BR>\n" );
document.write( "j = 3d + 9 - 3<BR>\n" );
document.write( "j = 3d + 6<BR>\n" );
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document.write( " Six years ago, her age was her daughter's age squared.<BR>\n" );
document.write( "j - 6 = (d-6)^2<BR>\n" );
document.write( "j - 6 = d^2 - 12d + 36<BR>\n" );
document.write( "Replace j with (3d+6)<BR>\n" );
document.write( "3d + 6 - 6 = d^2 - 12d + 36<BR>\n" );
document.write( "A quadratic equation<BR>\n" );
document.write( "d^2 - 12d - 3d + 36 = 0<BR>\n" );
document.write( "d^2 - 15d + 36 = 0<BR>\n" );
document.write( "Factors to:<BR>\n" );
document.write( "(d-12)(d-3) = 0<BR>\n" );
document.write( "Two solutions<BR>\n" );
document.write( "d = 3<BR>\n" );
document.write( "d = 12 yrs is the solution that makes sense here<BR>\n" );
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document.write( "How old is Janice?<BR>\n" );
document.write( "We know j = 3d + 6<BR>\n" );
document.write( "j = 3(12) + 6<BR>\n" );
document.write( "j = 42 yrs <BR>\n" );
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document.write( "Check solutions in the equation: j - 6 = (d-6)^2<BR>\n" );
document.write( "42 - 6 = (12-6)^2<BR>\n" );
document.write( "36 = 6^2; confirms of our solutions<BR>\n" );
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document.write( "  </SPAN>\n" );
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