document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331627>Question 331627</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the total surface area of a cube whose sides are all 5ft by 7ft </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237711 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237711\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "No can do.  In the first place, if you really have a cube, then all 6 of the faces must be squares and squares have equal measure sides -- not 5 feet by 7 feet.  On the other hand, if you have a rectangular solid, it is possible that 4 of the 6 faces could be 5 by 7, but the remaining two faces in that case must be squares -- either 5 by 5 or 7 by 7.\r<BR>\n" );
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document.write( "Figure out the area of each of the 6 faces of your solid figure, then add up the 6 areas.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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