document.write( "Question 331423: 2x^2-3x=5 completing the square \n" ); document.write( "
Algebra.Com's Answer #237702 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 2x^2-3x=5 completing the square \n" ); document.write( "; \n" ); document.write( "We need the coefficient of x^2, to be 1, divide each term by 2, and you have \n" ); document.write( "x^2 - \n" ); document.write( ": \n" ); document.write( "x^2 - \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "x^2 - \n" ); document.write( ": \n" ); document.write( "x^2 - \n" ); document.write( ": \n" ); document.write( "x^2 - \n" ); document.write( ": \n" ); document.write( "(x - \n" ); document.write( ": \n" ); document.write( "Find the square root of both sides \n" ); document.write( "x - \n" ); document.write( ": \n" ); document.write( "x = \n" ); document.write( "a perfect square \n" ); document.write( "x = \n" ); document.write( "Two solutions \n" ); document.write( "x = \n" ); document.write( "x = \n" ); document.write( "x = 2 \n" ); document.write( "and \n" ); document.write( "x = \n" ); document.write( "x = \n" ); document.write( "x = -1 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in original equation using x=2.5 \n" ); document.write( "2(2.5^2) -3(2.5) = 5 \n" ); document.write( "2(6.25) - 7.5 = 5 \n" ); document.write( "12.5 - 7.5 = 5; confirms our solution, \n" ); document.write( ": \n" ); document.write( "You can check solution for x=-1 \n" ); document.write( " |