document.write( "Question 331605: how do you arrange these physics equations\r
\n" ); document.write( "\n" ); document.write( "t=2pi sqrt((r^3)/(gm)) solve for m\r
\n" ); document.write( "\n" ); document.write( "a/b + c= a/d solve for b\r
\n" ); document.write( "\n" ); document.write( "d = vt + (1/2)at2 solve for v
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Algebra.Com's Answer #237685 by texttutoring(324)\"\" \"About 
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t=2pi sqrt((r^3)/(gm))\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by 2Pi\r
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\n" ); document.write( "\n" ); document.write( "T/2Pi = sqrt(r^3/gm)\r
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\n" ); document.write( "\n" ); document.write( "Square both sides:\r
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\n" ); document.write( "\n" ); document.write( "(T/2Pi)^2 = r^3/gm\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by m:\r
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\n" ); document.write( "\n" ); document.write( "m*(T/2Pi)^2 = r^3/g\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by (T/2Pi)^2:\r
\n" ); document.write( "\n" ); document.write( "m = (r^3/g)(2Pi/T)^2\r
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\n" ); document.write( "\n" ); document.write( "Next question: a/b + c= a/d\r
\n" ); document.write( "\n" ); document.write( "a/b=a/d -c
\n" ); document.write( "a = (a/d-c)b
\n" ); document.write( "a/(a/d - c) = b\r
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\n" ); document.write( "\n" ); document.write( "Last question: d = vt + (1/2)at^2\r
\n" ); document.write( "\n" ); document.write( "d = vt + (1/2)at^2
\n" ); document.write( "d - (1/2)at^2 = vt\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by t:\r
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\n" ); document.write( "\n" ); document.write( "d/t - (1/2)at = v
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