document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331599>Question 331599</A>: <I><SPAN STYLE=\"word-break: break-all;\"> graph: y= x^2 + 5x + 6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237679 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237679\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a parabola in general form. The easiest way to graph it is to turn it into standard form [y=a(x-p)^2+q], by completing the square.\r<BR>\n" );
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document.write( "y=x^2 +5x+6\r<BR>\n" );
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document.write( "Halve the b term (b=5 in this equation), then square it. (5/2)^2 = 25/4\r<BR>\n" );
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document.write( "Add this number to the first two terms, but then subtract it from the end (so that you are only adding zero to the equation).\r<BR>\n" );
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document.write( "y = x^2 +5x +25/4 +6 -25/4<BR>\n" );
document.write( "y = (x+5/2)^2 -1/4\r<BR>\n" );
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document.write( "You can now see where the parabola is. It is at (p,q) = (-5/2, -1/4)\r<BR>\n" );
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document.write( "Plot this point, then draw a parabola, opening up from that point. Follow the same trend as normal, with y=x^2 as your guide.\r<BR>\n" );
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document.write( "Example, go right/left 1, up 1. right/left 2, up 4, right/left 3, up 9, right/left 4, up 16... and  so on.\r<BR>\n" );
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document.write( "Here's a graph of your parabola: http://www.wolframalpha.com/input/?i=y+%3D+(x%2B5/2)^2+-1/4 </SPAN>\n" );
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