document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331524>Question 331524</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man's age is 3 times the sum of the ages of his two sons.after 5years his age will be twice the sum of the ages of his two sons.find the age of the man.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237589 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237589\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let age of sons be x & y & father's age =z<BR>\n" );
document.write( "z = 3(x+y)<BR>\n" );
document.write( "z/3 = (x+y)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "after 5 years<BR>\n" );
document.write( "their ages will be<BR>\n" );
document.write( "x+5, y+5, z+5<BR>\n" );
document.write( "z+5=2(x+5+y+5)<BR>\n" );
document.write( "z+5=2x+2y+20<BR>\n" );
document.write( "z+5=2(x+y)+20<BR>\n" );
document.write( "z+5-20=2(x+y)+20-20<BR>\n" );
document.write( "z-15=2(x+y)<BR>\n" );
document.write( "But (x+y)= z/3<BR>\n" );
document.write( "z-15=2*z/3<BR>\n" );
document.write( "multiply 3<BR>\n" );
document.write( "3*(z-15)=2z<BR>\n" );
document.write( "3z-45=2z<BR>\n" );
document.write( "3z-2z=45<BR>\n" );
document.write( "z=45  father's age </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );