document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331525>Question 331525</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The surface area of two cups are in the ratio 9:64 .if the smaller cup has a height of 25 cm and a volume of 2400 cm^3 calculate<BR>\n" );
document.write( "a)the height of larger cup.<BR>\n" );
document.write( "b)the volume of larger cup. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237588 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237588\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> volume of cylinder = pir^2h<BR>\n" );
document.write( "smaller cup<BR>\n" );
document.write( "volume = 2400= pi*r^2*25<BR>\n" );
document.write( "r^2=2400/(pi*25)<BR>\n" );
document.write( "r=sqrt(2400/(pi*25)<BR>\n" );
document.write( "r=5.3 cm<BR>\n" );
document.write( "..<BR>\n" );
document.write( "surface area of smaller cup = 2*pi*r*h<BR>\n" );
document.write( "S=2*pi*5.3*25<BR>\n" );
document.write( "S= 832.5 sq. cm<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Ratio of surface area = 9/64<BR>\n" );
document.write( "9/64= 832.5/x<BR>\n" );
document.write( "x=64*832.5/9<BR>\n" );
document.write( "= 5920 sq. cm is the surface area of larger cup </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );