document.write( "Question 331440: If two planes leave the same airport at 1:00 PM, how many miles apart will they be at 3:00 PM if one travels directly north at 150 mph and the other travels directly west at 200 mph? \r
\n" ); document.write( "\n" ); document.write( "I try the following but did not get the correct solution:\r
\n" ); document.write( "\n" ); document.write( "Plane A travels North 150 mph and Plane B travels West at 200 mph.\r
\n" ); document.write( "\n" ); document.write( "From 1:00 PM to 3:00 PM--> Plane A has traveled for two hours (150 + 150) = 300
\n" ); document.write( "Plane B has traveled for two hours (200 + 200) = 400\r
\n" ); document.write( "\n" ); document.write( "So, 400 - 300 = 100 miles apart?\r
\n" ); document.write( "\n" ); document.write( "Or is it a pythagoream problem...using the a^2 + b^2 = c^2 which would be \r
\n" ); document.write( "\n" ); document.write( "150^2 + b^2 = 300^2\r
\n" ); document.write( "\n" ); document.write( "= 22500 + b^2 = 90000
\n" ); document.write( "= b^2 = 9000-22500
\n" ); document.write( "= b^2 = 67500
\n" ); document.write( "= b = square root of 67500
\n" ); document.write( "which would be 259.8 miles apart\r
\n" ); document.write( "\n" ); document.write( "or could it be the following...\r
\n" ); document.write( "\n" ); document.write( "Plane A is 50 miles behind which means Plane B is 50 miles ahead...
\n" ); document.write( "so Plane B will be 100 miles ahead and that gives me 150 + 200 + 150 = 500 miles apart? \r
\n" ); document.write( "\n" ); document.write( "If so, is there a quicker way of finding it using an equation? Or can you answer it in a more simpler way?
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Algebra.Com's Answer #237554 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
If two planes leave the same airport at 1:00 PM, how many miles apart will they be at 3:00 PM if one travels directly north at 150 mph and the other travels directly west at 200 mph?
\n" ); document.write( "I try the following but did not get the correct solution:
\n" ); document.write( "Plane A travels North 150 mph and Plane B travels West at 200 mph.
\n" ); document.write( "From 1:00 PM to 3:00 PM--> Plane A has traveled for two hours (150 + 150) = 300
\n" ); document.write( "Plane B has traveled for two hours (200 + 200) = 400
\n" ); document.write( "So, 400 - 300 = 100 miles apart?
\n" ); document.write( "Or is it a pythagoream problem...using the a^2 + b^2 = c^2 which would be
\n" ); document.write( "150^2 + b^2 = 300^2
\n" ); document.write( "= 22500 + b^2 = 90000
\n" ); document.write( "= b^2 = 9000-22500
\n" ); document.write( "= b^2 = 67500
\n" ); document.write( "= b = square root of 67500
\n" ); document.write( "---------------------------------
\n" ); document.write( "It can be solved using Pythagoras, but the distance is the hypotenuse.
\n" ); document.write( "You solved for one of the legs.
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\n" ); document.write( "c^2 = 300^2 + 400^2
\n" ); document.write( "c = 500 miles
\n" ); document.write( "--------------------------------
\n" ); document.write( "which would be 259.8 miles apart
\n" ); document.write( "or could it be the following...
\n" ); document.write( "Plane A is 50 miles behind which means Plane B is 50 miles ahead...
\n" ); document.write( "so Plane B will be 100 miles ahead and that gives me 150 + 200 + 150 = 500 miles apart?
\n" ); document.write( "If so, is there a quicker way of finding it using an equation? Or can you answer it in a more simpler way?
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