document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38268>Question 38268</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 8 less than another. If 5 times the smaller number minus 2 times the larger number is 14, find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23755 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the larger number x.<BR>\n" );
document.write( "The smaller is then x - 8.<BR>\n" );
document.write( "From the English in the problem, we convert to an algebraic equation...<BR>\n" );
document.write( "5(x - 8) - 2x = 14<BR>\n" );
document.write( "5x - 40 - 2x = 14<BR>\n" );
document.write( "3x - 40 = 14<BR>\n" );
document.write( "3x = 54<BR>\n" );
document.write( "x = 18<BR>\n" );
document.write( "x - 8 = 10<BR>\n" );
document.write( "and we're done... </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );