document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331449>Question 331449</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 13.In a field there are twice as many birds as cows and one-third as many horses as birds.There are 640 legs in all.If no animal is missing a leg, how many animals are there?\r<BR>\n" );
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document.write( "a.60<BR>\n" );
document.write( "b.120<BR>\n" );
document.write( "c.220<BR>\n" );
document.write( "d.260<BR>\n" );
document.write( "e.300<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237543 by </B><A HREF=/tutors/aboutme.mpl?userid=mathmandotcom><B>mathmandotcom(31)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathmandotcom><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237543\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x= number of cows<BR>\n" );
document.write( "then 2x=the number of birds<BR>\n" );
document.write( "and(1/3)2x=the number of horses<BR>\n" );
document.write( "if each cow and horse has 4 legs and each bird has 2 legs then<BR>\n" );
document.write( "total number of legs=4(number of cows+number of horses)+2(number of birds)=640<BR>\n" );
document.write( "#legs=4(x+2/3*x)+2(2x)=640  multiply and simplify we get<BR>\n" );
document.write( "640=4x+8/3*x+4x<BR>\n" );
document.write( "640=8x+8/3*x   multiply by 3 <BR>\n" );
document.write( "1920=24x+8x<BR>\n" );
document.write( "1920=32x       divide by 32 we get<BR>\n" );
document.write( "x=60  # of cows<BR>\n" );
document.write( "2(60)=120= # of birds<BR>\n" );
document.write( "1/3(2*60)=40= # of horses\r<BR>\n" );
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document.write( "cows +birds+horses=60+120+40=220<BR>\n" );
document.write( "total number of animals is 220       answer is C<BR>\n" );
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