document.write( "Question 331277: Albert buys and sells books, and always purchase it at the same price. He then sells the books for $5 more than what he paid for. Two months before, he broke even after buying 56 books and selling 49. What is his buying price and selling price? \n" ); document.write( "
Algebra.Com's Answer #237539 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Albert buys and sells books, and always purchase it at the same price. \n" ); document.write( " He then sells the books for $5 more than what he paid for. \n" ); document.write( "Two months before, he broke even after buying 56 books and selling 49. \n" ); document.write( " What is his buying price and selling price? \n" ); document.write( ": \n" ); document.write( "Let x = the buying price \n" ); document.write( "and \n" ); document.write( "(x+5) = the selling price \n" ); document.write( ": \n" ); document.write( "56x = 49(x+5) \n" ); document.write( "56x = 49x + 245 \n" ); document.write( "56x - 49x = 245 \n" ); document.write( "7x = 245 \n" ); document.write( "x = \n" ); document.write( "x = $35 is the buying price \n" ); document.write( "obviously \n" ); document.write( "35 + 5 = $40 is the selling price \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution \n" ); document.write( "56(35) = 1960 \n" ); document.write( "49(40) = 1960 \n" ); document.write( " |