document.write( "Question 331405: solve the system x+y+z=-1
\n" );
document.write( "x-y+3z=-17
\n" );
document.write( "2x+y+z=-2 \n" );
document.write( "
Algebra.Com's Answer #237535 by mathmandotcom(31)![]() ![]() ![]() You can put this solution on YOUR website! three equations and three unknows x,y,z\r \n" ); document.write( "\n" ); document.write( "1) x+y+z=1 \n" ); document.write( "2) x-y+3z=17 Lets take equation 1 and 2 then eliminate y by adding \n" ); document.write( "3) 2x+y+z=-2 1) x+y+z=1 \n" ); document.write( " 2) x-y+3z=17 adding we get equation 4) 2x+4z=18 \n" ); document.write( " next take eq 2 and 3 and eliminate the same variable y \n" ); document.write( " 2) x-y+3z=17 \n" ); document.write( " 3) 2x+y+z=-2 adding we get eq 5)3x+4z=15 \n" ); document.write( "2x+4z=18 and 3x+4z=15 multiply eq 4) by -1 and add\r \n" ); document.write( "\n" ); document.write( "-2x-4z=-18 \n" ); document.write( " 3x+4z=15 adding we get -2x+3x-4z+4z=-18+15......x=-3 plug -3 in eq 4 \n" ); document.write( "2*-3+4z=18...-6+4z=18 solve for z by adding 6 then divide by 4\r \n" ); document.write( "\n" ); document.write( "4z=24.........z=6 finialy use x=-3 asnd z=6 and plug into eq 1)\r \n" ); document.write( "\n" ); document.write( "-3+y+6=1......y+3=1........y=-2 so we get (-3,-2,6) plug these into eq 1) \n" ); document.write( "-3-2+6=1 to check 1=1 your solution is (-3,-2,6) \r \n" ); document.write( "\n" ); document.write( "I hope this is not to crowed, good luck! \n" ); document.write( " |