document.write( "Question 331405: solve the system x+y+z=-1
\n" ); document.write( "x-y+3z=-17
\n" ); document.write( "2x+y+z=-2
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Algebra.Com's Answer #237535 by mathmandotcom(31)\"\" \"About 
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three equations and three unknows x,y,z\r
\n" ); document.write( "\n" ); document.write( "1) x+y+z=1
\n" ); document.write( "2) x-y+3z=17 Lets take equation 1 and 2 then eliminate y by adding
\n" ); document.write( "3) 2x+y+z=-2 1) x+y+z=1
\n" ); document.write( " 2) x-y+3z=17 adding we get equation 4) 2x+4z=18
\n" ); document.write( " next take eq 2 and 3 and eliminate the same variable y
\n" ); document.write( " 2) x-y+3z=17
\n" ); document.write( " 3) 2x+y+z=-2 adding we get eq 5)3x+4z=15
\n" ); document.write( "2x+4z=18 and 3x+4z=15 multiply eq 4) by -1 and add\r
\n" ); document.write( "\n" ); document.write( "-2x-4z=-18
\n" ); document.write( " 3x+4z=15 adding we get -2x+3x-4z+4z=-18+15......x=-3 plug -3 in eq 4
\n" ); document.write( "2*-3+4z=18...-6+4z=18 solve for z by adding 6 then divide by 4\r
\n" ); document.write( "\n" ); document.write( "4z=24.........z=6 finialy use x=-3 asnd z=6 and plug into eq 1)\r
\n" ); document.write( "\n" ); document.write( "-3+y+6=1......y+3=1........y=-2 so we get (-3,-2,6) plug these into eq 1)
\n" ); document.write( "-3-2+6=1 to check 1=1 your solution is (-3,-2,6) \r
\n" ); document.write( "\n" ); document.write( "I hope this is not to crowed, good luck!
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