document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38279>Question 38279</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi! I am having difficulty trying to figure this problem out.  Any help or direction that you are able to provide in solving is most appreciated! \r<BR>\n" );
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document.write( "Two ships leave port at the same time.  Ship A sails north at a speed of 20mph while ship B sails east at a speed of 30mph.<BR>\n" );
document.write( "a.- Find an expression in terms of the time 't'(in hours) giving the distance between the two ships.<BR>\n" );
document.write( "b.- Using the expression obtained in part (a), find the distance between the two ships 2hr after leaving port. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23753 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23753\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET D BE THE DISTANCE BETWEEN THE 2 SHIPS & BWCAUSE THIS PROBLEM CAN BE REPRESENTED BY A RIGHT (90 DEGREE)TRIANGLE THEN A~2+B~2=D~2 SO\r<BR>\n" );
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document.write( "20~2+30~2=D~2 OR 400+900=D~2 OR 1300=D~2 OR D=SQRT1300 OR D=36.06 MILES AFTER 1 HOUR.\r<BR>\n" );
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document.write( "2 HOURS AFTER THEY LEAVE THEY ARE D~2=(2*20)~2+(2*30)~2 OR D~2=40~2+60~2 OR \r<BR>\n" );
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document.write( "D~2=1600+3600 OR D~2=5200 OR D=SQRT5200 OR D=72.11 MILES APART<BR>\n" );
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