document.write( "Question 331300: Factor the polynomial x^3+8x^2+19x+12 \n" ); document.write( "
Algebra.Com's Answer #237508 by jrfrunner(365)\"\" \"About 
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Factor the polynomial \"x%5E3%2B8x%5E2%2B19x%2B12\"\r
\n" ); document.write( "\n" ); document.write( "Since the highest degree is 3, there exist 3 roots to this poynomial\r
\n" ); document.write( "\n" ); document.write( "The real roots (there might be some complex roots) will be from the set
\n" ); document.write( " -/+1, -/+2, -/+3, -/+4,-/+6, -/+12\r
\n" ); document.write( "\n" ); document.write( "Use Discarte's sign rule
\n" ); document.write( "Number of positive roots P(x) ++++ no sign change, so no positive roots
\n" ); document.write( "number of negative roots P(-x) -+-+ 3 sign changes, so either 3 negative roots or 1 negative root and 2 complex roots\r
\n" ); document.write( "\n" ); document.write( "Since we know that at least one of the roots is negative, the roots are from
\n" ); document.write( "the set -1,-2,-3,-4,-6,-12
\n" ); document.write( "so experiment with -1 and see \"P%28-1%29=%28-1%29%5E3+%2B+8%28-1%29%5E2%2B19%28-1%29+%2B12+=+-1%2B8-19%2B12=0\" so -1 is a root.\r
\n" ); document.write( "\n" ); document.write( "Now apply either long division or synthetic division to reduce the polynomial by one degree yield \"x%5E2%2B7x%2B12\" this can be easily factored into (x+3)(x+4)\r
\n" ); document.write( "\n" ); document.write( "so the original polymial can be factord into
\n" ); document.write( "\"x%5E3%2B8x%5E2%2B19x%2B12+=+%28x%2B1%29%2A%28x%2B3%29%2A%28x%2B4%29\"
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