document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331372>Question 331372</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help:\r<BR>\n" );
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document.write( "The base of a triangle is 6 cm greater than the height.  The are is 56 cm^2.  Find the height and length of the base. </SPAN>\n" );
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document.write( "Let <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large x\"> represent the measure of the height.  Then the measure of the base is <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large x\ +\ 6\">.\r<BR>\n" );
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document.write( "The area of a triangle is the product of the base times the height divided by 2, so:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \frac{x(x\ +\ 6)}{2}\ =\ 56\">\r<BR>\n" );
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document.write( "Solve for <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large x\"> to get the height, add 6 to get the base.  Note: The resulting quadratic equation will have two roots.  Discard the negative root because you are looking for a positive measure of length.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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