document.write( "Question 331366: Flying against the wind, an airplane travels 5580 in 9 hours. Flying with the wind, the same plane travels 4200 in 5 hours. What is the rate of the plane in still air and what is the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #237493 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "You don't bother to mention the distance units that the plane travels. Not a real problem except that it makes rendering the units a bit awkward.\r
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\n" ); document.write( "\n" ); document.write( "The rate of the plane relative to the ground when flying against the wind is where is the rate in still air and is the rate of the wind. Flying with the wind, \r
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\n" ); document.write( "\n" ); document.write( "We know that distance equals rate times time, so:\r
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\n" ); document.write( "\n" ); document.write( "Putting the two equations into standard form:\r
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\n" ); document.write( "\n" ); document.write( "Solve the system of equations for and \r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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