document.write( "Question 331366: Flying against the wind, an airplane travels 5580 in 9 hours. Flying with the wind, the same plane travels 4200 in 5 hours. What is the rate of the plane in still air and what is the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #237489 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Flying against the wind, an airplane travels 5580 in 9 hours. Flying with the wind, the same plane travels 4200 in 5 hours. What is the rate of the plane in still air and what is the rate of the wind? \n" ); document.write( "------------------ \n" ); document.write( "5580 what? Furlongs? Miles? Nautical miles? \n" ); document.write( "I'll assume nautical miles, since that's what aircraft use. \n" ); document.write( "5580/9 = 620 knots \n" ); document.write( "4200/5 = 840 knots \n" ); document.write( "The airspeed is the average (620+840)/2 = 730 knots \n" ); document.write( "The \"speed in still air\" is called the airspeed. \n" ); document.write( "If the people writing the textbooks don't know that, they should not enter problems dealing with it. \n" ); document.write( "----------------------- \n" ); document.write( "The wind speed is the difference between airspeed and ground speed \n" ); document.write( "= 840 - 730 \n" ); document.write( "= 110 knots \n" ); document.write( "------------- \n" ); document.write( "Aircraft use knots, not mph, for speeds, and so do the weather forecasters. \n" ); document.write( "1 knot = 1 nautical mile per hour \n" ); document.write( " \n" ); document.write( " |