document.write( "Question 331273: My question is\r
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document.write( "2 + √3x = x/3\r
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document.write( "Show far I have worked out.\r
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document.write( "Multiply both sides by 3\r
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document.write( "3(2 + √3x) = x\r
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document.write( "Then expanded bracket out\r
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document.write( "6 + 3√3x = x\r
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document.write( "Don't no if I have done correct so far and what to do next.\r
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document.write( "Any help would be gratefully recieved.
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Algebra.Com's Answer #237471 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! My question is \n" ); document.write( "2 + √3x = x/3 \n" ); document.write( "Show far I have worked out. \n" ); document.write( "Multiply both sides by 3 \n" ); document.write( "3(2 + √3x) = x \n" ); document.write( "Then expanded bracket out \n" ); document.write( "6 + 3√3x = x \n" ); document.write( "That's right so far, continuing \n" ); document.write( ": \n" ); document.write( "subtract 6 from both sides \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Square both sides \n" ); document.write( "9(3x) = (x-6)^2 \n" ); document.write( "27x = x^2 - 12x + 36 \n" ); document.write( ": \n" ); document.write( "A quadratic equation \n" ); document.write( "x^2 - 12x - 27x + 36 = 0 \n" ); document.write( "x^2 - 39x + 36 = 0 \n" ); document.write( ": \n" ); document.write( "This equation requires the quadratic formula \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "In this problem; a=1; b=-39; c=36 \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Two solutions \n" ); document.write( " \n" ); document.write( "x = \n" ); document.write( "x = 38.054 \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "x = \n" ); document.write( "x = .946 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check both solutions in original equation, only x=38.054 is a valid solution \n" ); document.write( " |