document.write( "Question 331160: John can run a certain course in 9 min and henry can run it in 6 min. If they start opposite ends and run toward one another, how long will they run before they meet? \n" ); document.write( "
Algebra.Com's Answer #237434 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
John can run a certain course in 9 min and henry can run it in 6 min.
\n" ); document.write( "If they start opposite ends and run toward one another, how long will
\n" ); document.write( " they run before they meet?
\n" ); document.write( ":
\n" ); document.write( "Let d = the distance of the course
\n" ); document.write( "Let t = time for them to meet
\n" ); document.write( ":
\n" ); document.write( "Write a speed equation, speed = dist/time
\n" ); document.write( ":
\n" ); document.write( "John's speed + Henry's speed = combined speed
\n" ); document.write( "\"d%2F9\" + \"d%2F6\" = \"d%2Ft\"
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by 18t, results
\n" ); document.write( "2dt + 3dt = 18d
\n" ); document.write( ":
\n" ); document.write( "Divide thru by d
\n" ); document.write( "2t + 3t = 18
\n" ); document.write( "5t = 18
\n" ); document.write( "t = \"18%2F5\"
\n" ); document.write( "t = 3.6 minutes for them to meet
\n" ); document.write( "
\n" );