document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331260>Question 331260</A>: <I><SPAN STYLE=\"word-break: break-all;\">  What is the solution of the equation 2 log4 (5x) = 3? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237428 by </B><A HREF=/tutors/aboutme.mpl?userid=mathmandotcom><B>mathmandotcom(31)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathmandotcom><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237428\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve 2log4(5x)=3  I assume this reads 2 times log base 4 of 5x equals 3: solve\r<BR>\n" );
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document.write( "alog(b)=log(b^a) so 2lod4(5x)=log4((5x)^2)=3 we have log4(25x^2)=3\r<BR>\n" );
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document.write( "Using the inverse log rule Log b(a)=c you get a=b^c so<BR>\n" );
document.write( "log4(25x^2)=3   25x^2=4^3; 25x^2=64; x^2=64/25; x=sqroot(64/25)=8/5 </SPAN>\n" );
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