document.write( "Question 331163: solve by substitution method (linear equation) x-5y=4 and 3x-4y=12\r
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Algebra.Com's Answer #237399 by AAfter.Com(18)\"\" \"About 
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x-5y=4 => x = 5y + 4
\n" ); document.write( "3x-4y=12 => 3(5y + 4) - 4y = 12
\n" ); document.write( "=> 15y + 12 - 4y = 12
\n" ); document.write( "=> 11y = 0
\n" ); document.write( "=> y = 0
\n" ); document.write( "Hence, x = 5y + 4 = 5X0 + 4 = 4
\n" ); document.write( "Hence, the solution set is (4,0)
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