document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331156>Question 331156</A>: <I><SPAN STYLE=\"word-break: break-all;\"> John can run a certain course in 9 min and henry can run it in 6 min. If they start at opposite ends and run toward one another, how long will they run before they meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237391 by </B><A HREF=/tutors/aboutme.mpl?userid=Tutorteddy.Com><B>Tutorteddy.Com(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Tutorteddy.Com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237391\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the distance covered be s units.<BR>\n" );
document.write( "If both John and Henry meet after t min, then<BR>\n" );
document.write( "s = (s/9)Xt + (s/6)Xt, s being the total distance.<BR>\n" );
document.write( "=> 1 = t(1/9 + 1/6)<BR>\n" );
document.write( "=> 1 = t(5/18)<BR>\n" );
document.write( "=> t = 18/5 min </SPAN>\n" );
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