document.write( "Question 331147: Fred is 3 years older than his sister mary. In 7 years she will be six-sevenths of his age. how old are they? \n" ); document.write( "
Algebra.Com's Answer #237383 by mananth(16946)\"\" \"About 
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mary's age =x
\n" ); document.write( "fred's age will be x+3
\n" ); document.write( "..
\n" ); document.write( "after 7 years
\n" ); document.write( "mary's age = x+7
\n" ); document.write( "Fred's age = x+3+7 = x+10
\n" ); document.write( "..
\n" ); document.write( "x+7= 6/7 * (x+10)
\n" ); document.write( "multiply by 7
\n" ); document.write( "7(x+7)=(6/7)*7(x+10)
\n" ); document.write( "7x+49=6x+60
\n" ); document.write( "7x-6x= 60-49
\n" ); document.write( "x= 11 years - Mary's age
\n" ); document.write( "Fred's age = x+3 = 11+3=14
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