document.write( "Question 331147: Fred is 3 years older than his sister mary. In 7 years she will be six-sevenths of his age. how old are they? \n" ); document.write( "
Algebra.Com's Answer #237383 by mananth(16946)![]() ![]() You can put this solution on YOUR website! mary's age =x \n" ); document.write( "fred's age will be x+3 \n" ); document.write( ".. \n" ); document.write( "after 7 years \n" ); document.write( "mary's age = x+7 \n" ); document.write( "Fred's age = x+3+7 = x+10 \n" ); document.write( ".. \n" ); document.write( "x+7= 6/7 * (x+10) \n" ); document.write( "multiply by 7 \n" ); document.write( "7(x+7)=(6/7)*7(x+10) \n" ); document.write( "7x+49=6x+60 \n" ); document.write( "7x-6x= 60-49 \n" ); document.write( "x= 11 years - Mary's age \n" ); document.write( "Fred's age = x+3 = 11+3=14 \n" ); document.write( " \n" ); document.write( " |