document.write( "Question 331139: the measure of the supplement of an angle is 12 degrees greater than three times the measure of a complement. Find the measure of the angle.\r
\n" ); document.write( "\n" ); document.write( "180-12 = 3(x) but this does not work. the answer is 51 degrees. I don't know how to get it. \n" ); document.write( "
Algebra.Com's Answer #237376 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
the measure of the supplement of an angle is 12 degrees greater than three times the measure of a complement. Find the measure of the angle.\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "let angle be x
\n" ); document.write( "complement = 90-x
\n" ); document.write( "supplement = 180-x
\n" ); document.write( "..
\n" ); document.write( "180-x=3(90-x)+12\r
\n" ); document.write( "\n" ); document.write( "180-x =270-3x+12
\n" ); document.write( "add +x
\n" ); document.write( "180-x+x=270-3x+x+12
\n" ); document.write( "180=-2x+12 +270
\n" ); document.write( "add-12
\n" ); document.write( "180-12=-2x+12-12
\n" ); document.write( "-102=-2x\r
\n" ); document.write( "\n" ); document.write( "x=-102/-2
\n" ); document.write( "x=51
\n" ); document.write( " \n" ); document.write( "
\n" );