document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331082>Question 331082</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What quantity of 75 per cent acid solution must be mixed with a 30 per cent solution to produce 810 mL of a 50 per cent solution? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237354 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237354\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What quantity of 75 per cent acid solution must be mixed with a 30 per cent solution to produce 810 mL of a 50 per cent solution? <BR>\n" );
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document.write( "acid + acid = acid<BR>\n" );
document.write( "0.75x + 0.30(810-x) = 0.50*810<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "75x + 30*910 - 30x = 50*810<BR>\n" );
document.write( "45x = 20*810<BR>\n" );
document.write( "x = (4/9)(810)<BR>\n" );
document.write( "x = 4*90<BR>\n" );
document.write( "x = 360 mL (amt. of 75% solution needed for the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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