document.write( "Question 331016: A rectangular parking lot is 50 ft longer than it is wide. Determine the dimensions of the parking lot if it measures 250 ft diagonally. \n" ); document.write( "
Algebra.Com's Answer #237345 by checkley77(12844)\"\" \"About 
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A^2+B^2=C^2
\n" ); document.write( "50^2+(X+50)^2=250^2
\n" ); document.write( "2,500+X^2+100X+2,500=63,500
\n" ); document.write( "X^2+100X+5,000-62,500=0
\n" ); document.write( "X^2+100X-57,500=0
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%5D%29%2F%282%2Aa%29+\"
\n" ); document.write( "X=(-100+-SQRT[100^2-4*1*-57,500)/2*1
\n" ); document.write( "X=(-100+-SQRT10,00+230,000])/2
\n" ); document.write( "X=(-100+-SQRT240,000)/2
\n" ); document.write( "X=(-100+-489.9)/2
\n" ); document.write( "X=(-100+489.9)/2
\n" ); document.write( "X=389.9/2
\n" ); document.write( "X=194.95+50=244.96 ANS. FOR THE DIAGONAL.
\n" ); document.write( "PROOF:
\n" ); document.write( "50^2+244.95^2=250^2
\n" ); document.write( "2,500+60,000=62,500
\n" ); document.write( "62,500~62,500
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