document.write( "Question 331018: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers. \n" ); document.write( "
Algebra.Com's Answer #237337 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! LET X, X+2 & X+4 BE THE THREE EVEN INTEGERS. \n" ); document.write( "(X+4)^2=76+(X+2)^2 \n" ); document.write( "X^2+8X+16=76=X^2+4X+4 \n" ); document.write( "8X-4X=4+76-16 \n" ); document.write( "4X=64 \n" ); document.write( "X=64/4 \n" ); document.write( "X=16 ANS FOR THE SMALLEST INTEGER. \n" ); document.write( "16=2=18 FOR THE MIDDLE INTYEGER. \n" ); document.write( "16+4=20 FOR THE LARGEST INTEGER. \n" ); document.write( "PROOF: \n" ); document.write( "20^2=76+18^2 \n" ); document.write( "400=76+324 \n" ); document.write( "400=400 \n" ); document.write( " \n" ); document.write( " |