document.write( "Question 331018: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers. \n" ); document.write( "
Algebra.Com's Answer #237337 by checkley77(12844)\"\" \"About 
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LET X, X+2 & X+4 BE THE THREE EVEN INTEGERS.
\n" ); document.write( "(X+4)^2=76+(X+2)^2
\n" ); document.write( "X^2+8X+16=76=X^2+4X+4
\n" ); document.write( "8X-4X=4+76-16
\n" ); document.write( "4X=64
\n" ); document.write( "X=64/4
\n" ); document.write( "X=16 ANS FOR THE SMALLEST INTEGER.
\n" ); document.write( "16=2=18 FOR THE MIDDLE INTYEGER.
\n" ); document.write( "16+4=20 FOR THE LARGEST INTEGER.
\n" ); document.write( "PROOF:
\n" ); document.write( "20^2=76+18^2
\n" ); document.write( "400=76+324
\n" ); document.write( "400=400
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