document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330651>Question 330651</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the measure of the central angle if the arc length is 20.21 and the circumference is 40.44? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237309 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237309\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a complete distance around the circle is the circumference = theta*r or 2*pi*r <BR>\n" );
document.write( "representing an arc around the circle. Thetha is the angle in raidants.\r<BR>\n" );
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document.write( "therefore the distance of an arc  S= Thetha * r <BR>\n" );
document.write( "given S=20.21 and the circumference = 40.44 <BR>\n" );
document.write( "r=Circumference/(2Pi) = 20.22/Pi<BR>\n" );
document.write( "Since S=thetha * r  solve for Thetha (the central angle in radiants)<BR>\n" );
document.write( "Theta = S/r = 20.21/(20.22/Pi) = Pi*(20.21/20.22) = 0.9995*Pi in radiants<BR>\n" );
document.write( "or Theta = 0.9995*Pi * (180/Pi) = 179.9 degrees\r<BR>\n" );
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document.write( "Theta = S/r = 20.21/(4.4 </SPAN>\n" );
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