document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330992>Question 330992</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 32 feet long. One leg is 2 feet longer than the other. Find the length of the shorter leg. Round your answer to the nearest hundredth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237300 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237300\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Try this:<BR>\n" );
document.write( "Let x be the length of the shorter leg and x+2 be the length of the other leg.<BR>\n" );
document.write( "Applying the Pythagorean theorem, we get:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=32%5E2+=+x%5E2%2B%28x%2B2%29%5E2 ALIGN=MIDDLE  ALT=\"32%5E2+=+x%5E2%2B%28x%2B2%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1024+=+2x%5E2%2B4x%2B4 ALIGN=MIDDLE  ALT=\"1024+=+2x%5E2%2B4x%2B4\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 1024 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2%2B4x-1020+=+0 ALIGN=MIDDLE  ALT=\"2x%5E2%2B4x-1020+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide both sides by 2 to simplify a bit.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B2x-510+=+0 ALIGN=MIDDLE  ALT=\"x%5E2%2B2x-510+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Solve this by the quadratic formula:<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a ALIGN=MIDDLE  ALT=\"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\"   DISABLED_style= \"max-width:90%; height:auto;\" > where: a = 1, b = 2, and c = -510<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-2%2B-sqrt%282%5E2-4%281%29%28-510%29%29%29%2F2%281%29 ALIGN=MIDDLE  ALT=\"x+=+%28-2%2B-sqrt%282%5E2-4%281%29%28-510%29%29%29%2F2%281%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "You can work this out on your calculator and you should get:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-23.605 ALIGN=MIDDLE  ALT=\"x+=+-23.605\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+21.605 ALIGN=MIDDLE  ALT=\"x+=+21.605\"   DISABLED_style= \"max-width:90%; height:auto;\" > Discard the negative solution, and your answer is:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+21.61 ALIGN=MIDDLE  ALT=\"x+=+21.61\"   DISABLED_style= \"max-width:90%; height:auto;\" >Rounded to the nearest hundredth. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );