document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330965>Question 330965</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have worked this problem several times and just want to be sure I did it correctly.  I am supposed to solve with elimination.\r<BR>\n" );
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document.write( "2r-5s=-7<BR>\n" );
document.write( "5r-2s=55<BR>\n" );
document.write( "I came up with the solution of (289/21, 145/21)<BR>\n" );
document.write( "Can anyone tell me if this is correct? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237295 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiplying 1st equation by -5 ___ -10r + 25s = 35\r<BR>\n" );
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document.write( "multiplying 2nd equation by 2 ___ 10r - 4s = 110\r<BR>\n" );
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document.write( "adding resulting equations (eliminating r) ___ 21s = 145 ___ s = 145/21\r<BR>\n" );
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document.write( "substituting ___ 2r - 5(145/21) = -7 ___ 42r - 725 = -147 ___ 42r = 578 ___ r = 289/21 </SPAN>\n" );
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