document.write( "Question 329671: k3' = k3k5/ k4+k5
\n" ); document.write( "k1' = k1A(k3'/k3'+k2)\r
\n" ); document.write( "\n" ); document.write( "Unsure how to substitute k3' into second equation and simplify. Please help, step by step explaination is better.
\n" ); document.write( "Thanks \n" ); document.write( "

Algebra.Com's Answer #237210 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
I hope it's OK that I change some of your variables.
\n" ); document.write( "B=k3
\n" ); document.write( "C=k3'
\n" ); document.write( "D=k4
\n" ); document.write( "E=k5
\n" ); document.write( "F=k1
\n" ); document.write( "G=k1'
\n" ); document.write( "H=k2\r
\n" ); document.write( "\n" ); document.write( "k3' = k3k5/ k4+k5
\n" ); document.write( "1. $\"C=BE%2F%28D%2BE%29\"$
\n" ); document.write( "k1' = k1A(k3'/k3'+k2)
\n" ); document.write( "2. $\"G=FAC%2F%28C%2BH%29\"$
\n" ); document.write( "Substitute eq. 1 into eq. 2,
\n" ); document.write( " $\"G=%28FA%28BE%2F%28D%2BE%29%29%29%2F%28%28BE%2F%28%28D%2BE%29%2BH%29%29%29\"$
\n" ); document.write( "Multiply numerator and denominator by $\"%28D%2BE%29\"$
\n" ); document.write( " $\"G=FABE%2F%28BE%2B%28D%2BE%29H%29\"$
\n" ); document.write( " $\"G=FABE%2F%28BE%2BDH%2BEH%29\"$
\n" ); document.write( ".
\n" ); document.write( ".
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\n" ); document.write( "k1'=(k1*A*k3*k5)/(k3*k5+k4*k2+k5*k2)\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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