document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330495>Question 330495</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the lengths of a pair of opposite sides of a rectangle were doubled and the other pair of opposite sides were each decreased by 14 m, the new rectangle would be a square with a perimeter of 84 m. Find the rectangle's original dimensions. ........ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237176 by </B><A HREF=/tutors/aboutme.mpl?userid=privani><B>privani(34)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=privani><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237176\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Understood from question:<BR>\n" );
document.write( "Square's perimeter = 84m, with sides \"s\"<BR>\n" );
document.write( "Hence,<BR>\n" );
document.write( "4s = 84<BR>\n" );
document.write( "s = 84/4<BR>\n" );
document.write( "s = 21\r<BR>\n" );
document.write( "\n" );
document.write( "Further from question:<BR>\n" );
document.write( "\"a pair of opposite sides of a rectangle were doubled\"; assuming this side is \"x\"<BR>\n" );
document.write( "2x = 21<BR>\n" );
document.write( "x = 21/2<BR>\n" );
document.write( "x = 10.5\r<BR>\n" );
document.write( "\n" );
document.write( "\"the other pair of opposite sides were each decreased by 14 m\"; assuming the other side is \"y\"<BR>\n" );
document.write( "y - 14 = 21<BR>\n" );
document.write( "y = 21 + 14<BR>\n" );
document.write( "y = 35\r<BR>\n" );
document.write( "\n" );
document.write( "So, the rectangle's original dimension is 10.5 m x 35 m. </SPAN>\n" );
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