document.write( "Question 330781: Will someone please help me with this story problem that has been a struggle for me.
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document.write( "Trains A and B are traveling in the same direction on parrellel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 125 miles per hour. Train A passes a station at 2:25PM. If train B passes the same station at 2:37PM at what time will train B catch up to train A?\r
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document.write( "When will train B catch up to train A? ___:___ am or pm?\r
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document.write( "Thanks for your help. \n" );
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Algebra.Com's Answer #237138 by mananth(16946) You can put this solution on YOUR website! Trains A and B are traveling in the same direction on parrellel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 125 miles per hour. Train A passes a station at 2:25PM. If train B passes the same station at 2:37PM at what time will train B catch up to train A?\r \n" ); document.write( "\n" ); document.write( "When will train B catch up to train A? ___:___ am or pm?\r \n" ); document.write( "\n" ); document.write( "difference in time when the trains passes the station is 12 minutes = 1/5 hours. \n" ); document.write( "speed of train B = 125 mph \n" ); document.write( "speed of Train A = 100 mph \n" ); document.write( "In 1/5 hour train A has traveled 1/5 *100 = 20 miles. \n" ); document.write( "difference in speed = 25 mph. \n" ); document.write( "Train B will catch up 25 miles every hour. \n" ); document.write( "To catch up 20 miles it will take 20/25 hours \n" ); document.write( "=4/5 hours = 48 minutes \n" ); document.write( "So Train B will catch up with train A at 2.37 + 0.48 minutes = 3.25 pm \n" ); document.write( " |