document.write( "Question 330746: Factor completely. 49a^2+4-28a \n" ); document.write( "
Algebra.Com's Answer #237120 by neatmath(302)\"\" \"About 
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\"49a%5E2%2B4-28a\"
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\n" ); document.write( "\n" ); document.write( "\"49a%5E2-28a%2B4\"
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\n" ); document.write( "\n" ); document.write( "We must use the factors of the first term to see how this can be factored, using either 49 and 1, or 7 and 7.
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\n" ); document.write( "\n" ); document.write( "\"%2849a-somenumber%29%28a-somenumber%29\" or \"%287a-somenumber%29%287a-somenumber%29\"
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\n" ); document.write( "\n" ); document.write( "Notice that both factors must have a negative sign in them, since the last term is positive, but the middle term is negative.
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\n" ); document.write( "\n" ); document.write( "Then we just have to use the factors of 4 to see what numbers will work to factor this.
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\n" ); document.write( "\n" ); document.write( "This is just a matter of guessing and checking, or trial and error. Factors of 4 are 4 and 1, or 2 and 2. So our answer MUST be one of the following, if this polynomial is factorable:
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\n" ); document.write( "\n" ); document.write( "\"%2849a-4%29%28a-1%29\" or \"%2849a-1%29%28a-4%29\" or \"%2849a-2%29%2849a-2%29\" or
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\n" ); document.write( "\n" ); document.write( "\"%287a-4%29%287a-1%29\" or \"%287a-2%29%287a-2%29\"
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\n" ); document.write( "\n" ); document.write( "Upon closer inspection, we can see that:
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\n" ); document.write( "\n" ); document.write( "\"%287a-2%29%287a-2%29\" does indeed multiply out to \"49a%5E2-28a%2B4\"
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\n" ); document.write( "\n" ); document.write( "so the answer is \"%287a-2%29%287a-2%29\"
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\n" ); document.write( "\n" ); document.write( "This polynomial is a special one, in the form of:
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\n" ); document.write( "\n" ); document.write( "\"a%5E2-2ab%2Bb%5E2=%28a-b%29%5E2\"
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\n" ); document.write( "\n" ); document.write( "where \"a=7a\" and \"b=2\"
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\n" ); document.write( "\n" ); document.write( "Factoring polynomials is hard, and it takes a lot of practice. There are also different ways to approach this problem, but I hope this helps!
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